document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=148721>Question 148721</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A city has a population of 20,000 people in the year 2000. If the population increases 5% per year, what will the population be in 2010? ( You are not summing the population over 2000-2010. Find the population in the year 2010, use a1r^n to solve.) \r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109059 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109059\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A city has a population of 20,000 people in the year 2000. If the population increases 5% per year, what will the population be in 2010? <BR>\n" );
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document.write( "Use the formula:<BR>\n" );
document.write( "A = 20000(1.05)^10<BR>\n" );
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document.write( "A = 20000 * 1.62889<BR>\n" );
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document.write( "A = 32,578 folks in 2010 </SPAN>\n" );
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