document.write( "Question 148736: Low-Fat yogurt. Ziggy's Famous Yogurt blends regular yogurt that is 3%fat with its no-fat yogurt to obtain low-fat yogurt that is 1%fat.How many pounds of regular yogurt and how many pounds of no-fat yogurt should be mixed to obtain 60 pounds of low-fat yogurt?\r
\n" ); document.write( "\n" ); document.write( "I started with x pounds=3% yogurt .03x
\n" ); document.write( " y pounds=no fat yogurt 0.0y
\n" ); document.write( " 60 pounds=1% yogurt .01(60) or .60
\n" ); document.write( " x+y=60 and .03x + 0.0y =.60
\n" ); document.write( " x=60-y
\n" ); document.write( " .03x = .60
\n" ); document.write( " .03(60-y)=.60
\n" ); document.write( " 1.80-y=.60
\n" ); document.write( " y=1.20\r
\n" ); document.write( "\n" ); document.write( " x+y=.60
\n" ); document.write( " x+1.20=.60
\n" ); document.write( " x=.60-1.20
\n" ); document.write( " x=-.60
\n" ); document.write( " I am lost and confused , please help me understand how to do this word problem
\n" ); document.write( "Thank you\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #109057 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
1.\"x%2By=60\"
\n" ); document.write( "2.\".03x=.60\"
\n" ); document.write( "Your equations are correct.
\n" ); document.write( "You could have solved eq. 2 directly to get x=..., then substitute back into 1 to solve for y.
\n" ); document.write( "\"0.03x=0.60\"
\n" ); document.write( "\"x=20\"
\n" ); document.write( "\"y=60-x\"
\n" ); document.write( "\"y=40\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( "Let's see where you went wrong.
\n" ); document.write( "\"x=60-y\"
\n" ); document.write( "\".03x+=+.60\"
\n" ); document.write( "\".03%2860-y%29=.60\"
\n" ); document.write( "\"1.80-highlight%28y%29=.60\"<---- Here's where you went wrong.
\n" ); document.write( "You didn't distribute 0.03 through the entire expression.
\n" ); document.write( "Here's what it should have been.
\n" ); document.write( "\".03%2860-y%29=.60\"
\n" ); document.write( "\".03%2860%29-0.03y=.60\"
\n" ); document.write( "\"1.8-0.03y=.60\"
\n" ); document.write( "\"-0.03y=-1.2\"
\n" ); document.write( "\"highlight%28y=40%29\"
\n" ); document.write( "\"x%2By=60\"
\n" ); document.write( "\"highlight%28x=20%29\"
\n" ); document.write( ".
\n" ); document.write( ".
\n" ); document.write( ".\r
\n" ); document.write( "\n" ); document.write( "You could have also done it this way to simplify.
\n" ); document.write( "Divide by 0.03 first, no need to distribute.
\n" ); document.write( "\".03%2860-y%29=.60\"
\n" ); document.write( "\"60-y=20\" Divide both sides by .03.
\n" ); document.write( "\"y=40\"
\n" ); document.write( " \n" ); document.write( "
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