document.write( "Question 148631: tan^2x-cot^2x=sec^2x-csc^2x \n" ); document.write( "

Algebra.Com's Answer #109042 by jojo14344(1513) $\"\"$ $\"About$

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Trigo Identities.
\n" ); document.write( "We should know that 1+(tan^2x)=sec^2x also 1+(cot^2x)=csc^2x
\n" ); document.write( "Substituting these identities to the eqn (tan^2x)-(cot^2x)=(sec^2x)-(csc^2x)
\n" ); document.write( " $\"%28sec%5E2x%29-1-%28csc%5E2-1%29=%28sec%5E2x%29-%28csc%5E2x%29\"$
\n" ); document.write( " $\"sec%5E2x-cross%281%29-csc%5E2x%2Bcross%281%29=sec%5E2x-csc%5E2x\"$
\n" ); document.write( " $\"sec%5E2x-csc%5E2x=sec%5E2x-csc%5E2x\"$ ----------> Identical
\n" ); document.write( " Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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