document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=148715>Question 148715</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Give vertex and axis of symmetry for f(x) = x ^2 + 2\r<BR>\n" );
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document.write( "(f(x)= x squared plus two\r<BR>\n" );
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document.write( "Not sure if the vertex should be (0,2) OR (0,-2) axis is 0.\r<BR>\n" );
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document.write( "I solved it by using the formula -b / 2a and then I substituted using the equation a^2 + bx +c.  <BR>\n" );
document.write( "thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #109037 by </B><A HREF=/tutors/aboutme.mpl?userid=oscargut><B>oscargut(2103)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=oscargut><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=oscargut><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=109037\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> f(x) = x ^2 + 2\r<BR>\n" );
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document.write( "then -b/2a = -0/2=0<BR>\n" );
document.write( "V=(0,f(0))=(0,2)\r<BR>\n" );
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document.write( "Axis: x=0 </SPAN>\n" );
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