document.write( "Question 148708: solve for all solutions\r
\n" ); document.write( "\n" ); document.write( "3tan^3 x=tan x \n" ); document.write( "
Algebra.Com's Answer #109032 by nabla(475)\"\" \"About 
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let tan x= u\r
\n" ); document.write( "\n" ); document.write( "3u^3=u
\n" ); document.write( "3u^3-u=0
\n" ); document.write( "u(3u^2-1)=0
\n" ); document.write( "so u=0 or 3u^2=1 which is the same as u=+/- 1/sqrt(3)\r
\n" ); document.write( "\n" ); document.write( "So we want
\n" ); document.write( "tan x =0
\n" ); document.write( "and
\n" ); document.write( "tan x=sinx/cosx=+/- sqrt(3)/3\r
\n" ); document.write( "\n" ); document.write( "tan x is 0 when sine is 0. That occurs at 0 degrees and 180 degrees, or 0 radians and pi radians.\r
\n" ); document.write( "\n" ); document.write( "The positive value for 1/sqrt(3) occurs at cos x=sqrt(3)/2 and sin x=1/2, AND cos x=-sqrt(3/2) and sinx=-1/2. Which is to say, 30 degrees or pi/6 radians AND 210 degrees or 7pi/6.\r
\n" ); document.write( "\n" ); document.write( "The negative value occurs at cos x=sqrt(3)/2 and sin x=-1/2 ----- or cos x=-sqrt(3)/2 and sin x=1/2. Respectively, these occur at 330 degrees which is 11pi/6, and at 150 degrees which is 5pi/6.\r
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\n" ); document.write( "\n" ); document.write( "So our entire solution set is:
\n" ); document.write( "x=0, x=pi/6, x=5pi/6, x=pi, x=7pi/6, x=11pi/6.
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