document.write( "Question 148676: A plane leaves an airport and flies south at 188 mph. Later, a second plane leaves the same airport and flies south at 470mph. If the second plane overtakes the first one in 2.5 hours, how long of a head start did the first plane have?\r
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document.write( "a. 2hr b. 3hr c.3.75 hr d. 4.75hr e. 6.25hr\r
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document.write( "I just can't figure this out. Please help. My e-mail address is kslau94828@aol.com
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Algebra.Com's Answer #109006 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A plane leaves an airport and flies south at 188 mph. Later, a second plane leaves the same airport and flies south at 470mph. If the second plane overtakes the first one in 2.5 hours, how long of a head start did the first plane have? \n" ); document.write( ": \n" ); document.write( "Let t = head start time in hrs \n" ); document.write( ": \n" ); document.write( "When one plane overtakes the other plane. they will have traveled the same distance \n" ); document.write( "Write a distance equation from this fact: Dist = speed * time \n" ); document.write( ": \n" ); document.write( "2nd plane travel time = 2.5 hrs \n" ); document.write( "1st plane travel time = (t+2.5) \n" ); document.write( ": \n" ); document.write( "188(t+2.5) = 470 * 2.5 \n" ); document.write( ": \n" ); document.write( "188t + 470 = 1175 \n" ); document.write( ": \n" ); document.write( "188t = 1175 - 470 \n" ); document.write( ": \n" ); document.write( "188t = 705 \n" ); document.write( "t = \n" ); document.write( "t = 3.75 hr head start \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check the solution by confirming that each plane traveled the same distance \n" ); document.write( "1st plane travel time: 2.5 + 3.75 = 6.25 \n" ); document.write( ": \n" ); document.write( "188 * 6.25 = 1175 mi \n" ); document.write( "470 * 2.5 = 1175 mi \n" ); document.write( " |