document.write( "Question 148398: In square units what is the area of triangle ADB
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document.write( "Given:
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document.write( " Triangle ABC
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document.write( "Triangle DBC
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document.write( "Triangle ADB
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document.write( "AD= 6
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document.write( "DC= 4
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document.write( "BC= 8
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document.write( "Angle ACB is a right angle
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document.write( "D is a point on line AC\r
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Algebra.Com's Answer #108962 by jojo14344(1513)![]() ![]() ![]() You can put this solution on YOUR website! If \"ACB\" forms a right triangle, you should have the following sides: \n" ); document.write( "\"AC\"= opposite side \n" ); document.write( "\"CB\"= adjacent side \n" ); document.write( "\"AB\"= hypotenuse side \n" ); document.write( "Now, there's a point in line \"AC\" called \"D\" and forms an obtuse triangle \"ADB\"-----> unknown Area? \n" ); document.write( ". \n" ); document.write( "Area=(1/2)*base*height -----> working equation \n" ); document.write( ". \n" ); document.write( "We have to remember that the \"base\" is always perpendicular to the \"height\" for the equation to work. The \"base\" is given which is \"AD\"= 6, but we can't use \"DB\" as height bec. is not perpendicular to \"AD\" right? \n" ); document.write( ". \n" ); document.write( "If you extend line AD to C meets line \"BC\" and forms 90 degree. Very good! As it is given, \"BC\"= 8 and we'll be the height of triangle \"ADB\". \n" ); document.write( "Going back to our working eq'n, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Thank you, \n" ); document.write( "Jojo \n" ); document.write( " |