document.write( "Question 148398: In square units what is the area of triangle ADB
\n" ); document.write( "Given:
\n" ); document.write( " Triangle ABC
\n" ); document.write( "Triangle DBC
\n" ); document.write( "Triangle ADB
\n" ); document.write( "AD= 6
\n" ); document.write( "DC= 4
\n" ); document.write( "BC= 8
\n" ); document.write( "Angle ACB is a right angle
\n" ); document.write( "D is a point on line AC\r
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Algebra.Com's Answer #108962 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
If \"ACB\" forms a right triangle, you should have the following sides:
\n" ); document.write( "\"AC\"= opposite side
\n" ); document.write( "\"CB\"= adjacent side
\n" ); document.write( "\"AB\"= hypotenuse side
\n" ); document.write( "Now, there's a point in line \"AC\" called \"D\" and forms an obtuse triangle \"ADB\"-----> unknown Area?
\n" ); document.write( ".
\n" ); document.write( "Area=(1/2)*base*height -----> working equation
\n" ); document.write( ".
\n" ); document.write( "We have to remember that the \"base\" is always perpendicular to the \"height\" for the equation to work. The \"base\" is given which is \"AD\"= 6, but we can't use \"DB\" as height bec. is not perpendicular to \"AD\" right?
\n" ); document.write( ".
\n" ); document.write( "If you extend line AD to C meets line \"BC\" and forms 90 degree. Very good! As it is given, \"BC\"= 8 and we'll be the height of triangle \"ADB\".
\n" ); document.write( "Going back to our working eq'n,
\n" ); document.write( "\"A=%281%2F2%29base%2Aheight=%281%2F2%29%28AD%29%28BC%29\"
\n" ); document.write( "\"A=%281%2F2%29%286%29%288%29\"
\n" ); document.write( "\"A=24+square+units\"
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo
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