document.write( "Question 148604: The value of a new $3500 sailboat decreases 10% per year. Find its value after 1 year. \n" ); document.write( "

Algebra.Com's Answer #108956 by mangopeeler07(462) $\"\"$ $\"About$

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Find 10% of 3500\r
\n" ); document.write( "\n" ); document.write( " $\"10%2F100=x%2F3500\"$ \r
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\n" ); document.write( "\n" ); document.write( "Cross multiply:
\n" ); document.write( " $\"3500=10x\"$ \r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 100
\n" ); document.write( " $\"350=x\"$ \r
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\n" ); document.write( "\n" ); document.write( "Subtract that from 3500
\n" ); document.write( " $\"3500-350\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3150\"$ \r
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\n" ); document.write( "\n" ); document.write( "Value after 1 year=$3150
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