document.write( "Question 148584: I hope I put the this problem in the right algebra field:\r
\n" ); document.write( "\n" ); document.write( "It seriously have problem with this equation:\r
\n" ); document.write( "\n" ); document.write( "Q= 0.001744*12*h^(2/3)+ 0.00091*h^(5/3)\r
\n" ); document.write( "\n" ); document.write( "I must get result in form:
\n" ); document.write( "h=...?\r
\n" ); document.write( "\n" ); document.write( "I got so far:
\n" ); document.write( "b*x^5 + a*x^2 - Q = 0 where x=h^(1/3) and a,b are coefficients
\n" ); document.write( "Now, I don't know how to contiune!
\n" ); document.write( "Help me, please!!!!
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Algebra.Com's Answer #108945 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
set Q=0 and factor\r
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\n" ); document.write( "\n" ); document.write( "0=(h^(2/3))(.001744*12+.00091h^(3/3))\r
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\n" ); document.write( "\n" ); document.write( "h^(2/3)=0 __ h=0\r
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\n" ); document.write( "\n" ); document.write( ".020928+.00091h=0 __ subtracting .020928 __ .00091h=-.020928 __ dividing by .00091 __ h=23 (approx)
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