document.write( "Question 148550: A regular pentagon can be dissected into 5 isosceles triangles whose vertex angle is at the center of the pentagon. The height of the triangle is 10 cm. find the area of this pentagon. \n" ); document.write( "
Algebra.Com's Answer #108888 by mangopeeler07(462)\"\" \"About 
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Pentagon=540 degrees
\n" ); document.write( "540/5=108
\n" ); document.write( "108=the vertex angle of the isosceles triangle\r
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\n" ); document.write( "\n" ); document.write( "1/2 of 108=54
\n" ); document.write( "tan(54)=x/10
\n" ); document.write( "x=13.764\r
\n" ); document.write( "\n" ); document.write( "(x=length of half of one side of the pentagon)
\n" ); document.write( "2x=27.528\r
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\n" ); document.write( "\n" ); document.write( "apothem=10
\n" ); document.write( "perimeter=137.638\r
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\n" ); document.write( "\n" ); document.write( "area=1/2ap\r
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\n" ); document.write( "\n" ); document.write( "137.638(10)=1376.38\r
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\n" ); document.write( "\n" ); document.write( "1376.38/2=688.19\r
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\n" ); document.write( "\n" ); document.write( "area=688.19\"cm%5E2\"
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