document.write( "Question 148547: THE SUM OF MR LEE'S AND HIS SON'S AGE IS 49. IN THREE YEARS TIME, HE WILL BE 4 TIMES AS OLD AS HIS SON. FIND THEIR PRESENT AGES \n" ); document.write( "
Algebra.Com's Answer #108884 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! THE SUM OF MR LEE'S AND HIS SON'S AGE IS 49. IN THREE YEARS TIME, HE WILL BE 4 TIMES AS OLD AS HIS SON. FIND THEIR PRESENT AGES \n" ); document.write( "----------- \n" ); document.write( "L = Mr. Lee's age \n" ); document.write( "S = Son's age \n" ); document.write( "---------- \n" ); document.write( "S+L = 49 \n" ); document.write( "L+3 = 4*(S+3) \n" ); document.write( "---------- \n" ); document.write( "Sub for L, L = 49-S \n" ); document.write( "49-S + 3 = 4*(S+3) \n" ); document.write( "52-S = 4S+12 \n" ); document.write( "40 = 5S \n" ); document.write( "S = 8 \n" ); document.write( "---- \n" ); document.write( "L = 49-S \n" ); document.write( "L = 41 \n" ); document.write( " \n" ); document.write( " |