document.write( "Question 148547: THE SUM OF MR LEE'S AND HIS SON'S AGE IS 49. IN THREE YEARS TIME, HE WILL BE 4 TIMES AS OLD AS HIS SON. FIND THEIR PRESENT AGES \n" ); document.write( "
Algebra.Com's Answer #108884 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
THE SUM OF MR LEE'S AND HIS SON'S AGE IS 49. IN THREE YEARS TIME, HE WILL BE 4 TIMES AS OLD AS HIS SON. FIND THEIR PRESENT AGES
\n" ); document.write( "-----------
\n" ); document.write( "L = Mr. Lee's age
\n" ); document.write( "S = Son's age
\n" ); document.write( "----------
\n" ); document.write( "S+L = 49
\n" ); document.write( "L+3 = 4*(S+3)
\n" ); document.write( "----------
\n" ); document.write( "Sub for L, L = 49-S
\n" ); document.write( "49-S + 3 = 4*(S+3)
\n" ); document.write( "52-S = 4S+12
\n" ); document.write( "40 = 5S
\n" ); document.write( "S = 8
\n" ); document.write( "----
\n" ); document.write( "L = 49-S
\n" ); document.write( "L = 41
\n" ); document.write( "
\n" ); document.write( "
\n" );