document.write( "Question 148503: If a figure forms the base with dimensions of 10ft x 10ft and the pyramids other dimensions are 12ft x 13ft what would the surface area be? \n" ); document.write( "

Algebra.Com's Answer #108856 by jojo14344(1513) $\"\"$ $\"About$

You can put this solution on YOUR website!
From what's given, it's a square base pyramid (because of 10 ft x 10 ft dimensions). The base is given, and you gave other dimensions = 12ft, suppposedly should be the height, and 13 ft should be the distance from the tip on the top going down slanted or diagonal on the body in right angle to the base. Sorry, I don't know if you can picture it. But the formula we'll use for Surface Area= (2*base*slanted height) + (base)^2
\n" ); document.write( " $\"SA=2%2A10ft%2A13ft+%2B+10%5E2\"$
\n" ); document.write( " $\"SA=260%2B100\"$
\n" ); document.write( " $\"SA=360square+ft\"$
\n" ); document.write( "If you noticed we didn't use the $\"height\"$ . We only need this if we're looking for the $\"+Volume\"$ .
\n" ); document.write( "Thank you,
\n" ); document.write( "Jojo \n" ); document.write( "

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