document.write( "Question 148518: A Student has scores of 73,79, and 81 on three government exams. What score does she need on a fourth exam to give her an average of 80 or better?\r
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Algebra.Com's Answer #108845 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "Let x=score on fourth exam\r
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\n" ); document.write( "\n" ); document.write( "So the average A of all 4 exams are\r
\n" ); document.write( "\n" ); document.write( "\"A=%2873%2B79%2B81%2Bx%29%2F4\"\r
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\n" ); document.write( "\n" ); document.write( "Since the average must be greater than or equal to 80, this means that the right side is greater than or equal to 80\r
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\n" ); document.write( "\n" ); document.write( "\"%2873%2B79%2B81%2Bx%29%2F4%3E=80\" Set the right side greater than 80\r
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\n" ); document.write( "\n" ); document.write( "\"73%2B79%2B81%2Bx%3E=320\" Multiply both sides by 4.\r
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\n" ); document.write( "\n" ); document.write( "\"x%2B233%3E=320\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E=320-233\" Subtract \"233\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x%3E=87\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the answer is \"x%3E=87\" which means that the student must get an 87 or better on the 4th exam. \r
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