document.write( "Question 148492: Two similar bottles of 'Sunshine Cola' have lengths that are 12cm and 15cm.
\n" ); document.write( "a) The volume of the large bottle is 1.5 litres. Calculate the volume of the smaller bottle.
\n" ); document.write( "b) The area of the label on the small bottle is 12cm squared. Calculate the area on the label of the large bottle.
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Algebra.Com's Answer #108834 by jojo14344(1513)\"\" \"About 
You can put this solution on YOUR website!
Well it is a cola in a bottle so we need to find the \"%22radius%22\" (very important) that we'll used in the calculations. Next, we'll assume it's a cola in can with cylindrical shape because ther'es no formula for finding area & volume for \"curvature\" bottle (2 curves? 3 curves?, we don't know)
\n" ); document.write( "1)For the \"Volume=pi%2Ar%5E2h\" where the height will be the lengths given.
\n" ); document.write( "Let's follow the following designation,
\n" ); document.write( "\"V%5B1%5D=pi%28r%5B1%5D%29%5E2%28h%5B1%5D%29\" -------------- smaller size
\n" ); document.write( "\"V%5B2%5D=pi%28r%5B2%5D%29%5E2%28h%5B2%5D%29\" -------------- bigger size
\n" ); document.write( "Since \"V%5B2%5D\" is given, we'll solve this first,
\n" ); document.write( "\"15liters=pi%28r%5B2%5D%29%5E2+%2815+centimeters%29\"
\n" ); document.write( "We have to remember, \"1Liter=1000+cm%5E3\"
\n" ); document.write( "\"%28r%5B2%5D%29%5E2=+%281500cm%5E3%29%2F%28pi%2A15cm%29\" \"r%5B2%5D=sqrt%2832%29\"
\n" ); document.write( "\"r%5B2%5D=+6+cm\" -----------> if you want exact =5.6 cm
\n" ); document.write( "And remember \"r%5B1%5D=r%5B2%5D\" because they're similar right as stated.
\n" ); document.write( "So for \"V%5B1%5D=pi%2856%29%5E2%2812cm%29\" \"V%5B1%5D=1182+cm%5E3\"= 1.18 Liters ---> smaller
\n" ); document.write( "2) for the Area of the bigger cola, we need to get the \"Area+of+the+ends%2B+Area+of+the+cylindrical+side\"= \"A%5B2%5D=2pi%28r%5B2%5D%29%5E2+%2B+2pi%28r%5B2%5D%29%28h%5B2%5D%29\"
\n" ); document.write( "\"A%5B2%5D=2pi%2856%29%5E2+%2B+2pi%2856%29%2815%29\"=\"197%2B528\"
\n" ); document.write( "\"A%5B2%5D=725+cm%5E2\" ------------> bigger\r
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Thank you,\r\n" );
document.write( "Jojo
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