document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=148486>Question 148486</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The diameter of circle AOB is 12, Triangle ABC is inscribed in the circle, angle A = 45. In cm squared what is the area of Triangle ABC, <BR>\n" );
document.write( "a) 18<BR>\n" );
document.write( "b) 108<BR>\n" );
document.write( "c) 144<BR>\n" );
document.write( "d) 36<BR>\n" );
document.write( "or e) 72   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #108813 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=108813\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First draw the inscribed triangle in the circle and label all of the sides and angles given. \r<BR>\n" );
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document.write( "Now draw in the radius from the center O to the angle ACB. Since the inscribed angle BAC is 45 degrees, this means that the central angle BOC is 90 degrees (remember the central angle is double the inscribed angle when they cut the same arc length). Now since the diameter is 12, this means that the radius is 6. So let's draw all of this info in:\r<BR>\n" );
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document.write( "Since OC is perpendicular to AB, this means that OC is the height and AB is the base\r<BR>\n" );
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document.write( "Now let's use the area of a triangle formula to find the area\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=%281%2F2%29%2Ab%2Ah ALIGN=MIDDLE  ALT=\"A=%281%2F2%29%2Ab%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" > Start with the known formula\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=%281%2F2%29%2A12%2A6 ALIGN=MIDDLE  ALT=\"A=%281%2F2%29%2A12%2A6\"   DISABLED_style= \"max-width:90%; height:auto;\" > Plug in <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b=12 ALIGN=MIDDLE  ALT=\"b=12\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h=6 ALIGN=MIDDLE  ALT=\"h=6\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=72%2F2 ALIGN=MIDDLE  ALT=\"A=72%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Multiply\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A=36 ALIGN=MIDDLE  ALT=\"A=36\"   DISABLED_style= \"max-width:90%; height:auto;\" > Reduce\r<BR>\n" );
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document.write( "So the area of the triangle is 36 square units. This means that the answer is choice d)<BR>\n" );
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