document.write( "Question 148461: The sum of the digits of a two-digit number is 7. The original two-digit number is 3 less than 4 times the number with its digits reversed. Find the original two-digit number.
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Algebra.Com's Answer #108794 by stanbon(75887)\"\" \"About 
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The sum of the digits of a two-digit number is 7.
\n" ); document.write( "The original two-digit number is 3 less than 4 times the number with its digits reversed.
\n" ); document.write( "Find the original two-digit number.
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\n" ); document.write( "Let the original number be 10t+u where t is the tens digit and u is the units digit.
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\n" ); document.write( "EQUATIONS:
\n" ); document.write( "t + u = 7
\n" ); document.write( "10t+u = 4(10u+t)-3
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\n" ); document.write( "Rearrange:
\n" ); document.write( "t + u = 7
\n" ); document.write( "6t -39u = -3
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\n" ); document.write( "Modify:
\n" ); document.write( "6t + 6u = 42
\n" ); document.write( "6t - 39u = -3
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\n" ); document.write( "Subtract to solve for \"u\":
\n" ); document.write( "45u = 45
\n" ); document.write( "u = 1
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\n" ); document.write( "Substitute into t+u = 7 to solve for \"t\":
\n" ); document.write( "t+1 = 7; t=6
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\n" ); document.write( "Original Number: 61
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
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