document.write( "Question 148457This question is from textbook
\n" ); document.write( ": A plane flying the 3458 mi. trip from New York City to London has a 50 mph tailwind. The flight's point of no return is the point at which the flight time required to return to New York is the same as the time required to continue on to London. If the speed of the plane in still air is 360 mph, how far is New York from the point of no return. \n" ); document.write( "
Algebra.Com's Answer #108793 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A plane flying the 3458 mi. trip from New York City to London has a 50 mph tailwind.
\n" ); document.write( "The flight's point of no return is the point at which the flight time required to return to New York is the same as the time required to continue on to London.
\n" ); document.write( "If the speed of the plane in still air is 360 mph, how far is New York from the point of no return.
\n" ); document.write( "------------
\n" ); document.write( "With the wind data:
\n" ); document.write( "rate = 360+50 = 410mph ; distance = x mi ; time = d/r = x/410
\n" ); document.write( "-------------------
\n" ); document.write( "Again the wind data:
\n" ); document.write( "rate = 360-50 =310 mph ; distance = (3458-x) mi ; time = d/r = (3458-x)/310
\n" ); document.write( "------------
\n" ); document.write( "EQUATION:
\n" ); document.write( "After going x miles from NY, time to go the remaining miles with the wind
\n" ); document.write( "equals time to return x miles against the wind.
\n" ); document.write( "time with = time against
\n" ); document.write( "x/310 = (3458-x)/410
\n" ); document.write( "410x = 310*3458 - 310x
\n" ); document.write( "720x = 310*3458
\n" ); document.write( "x = 1488.86 miles from NY is the point of no return
\n" ); document.write( "==============
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );