document.write( "Question 148432This question is from textbook algebra the easy way
\n" ); document.write( ": how are you? My first question is #10. ax/b + cx/d = e
\n" ); document.write( "and #11 a/bx + c/d=e; for both of them i need to solve for X. i dont know how to really disect this problem to solve for X, dont know each step for this complex fraction equation. Any help at all is greatly appreciated. thank you.
\n" ); document.write( "-Brian
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Algebra.Com's Answer #108778 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
My first question is #10. ax/b + cx/d = e
\n" ); document.write( "and #11 a/bx + c/d=e; for both of them i need to solve for X.
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\n" ); document.write( "10. ax/b + cx/d = e
\n" ); document.write( "Multiply by bd to eliminate fractions
\n" ); document.write( "adx + bcx = bde
\n" ); document.write( "x*(ad + bc) = bde
\n" ); document.write( "\"x+=+bde%2F%28ad%2Bbc%29\" that's all you can do, no further simplification is possible.
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\n" ); document.write( "11. a/bx + c/d=e
\n" ); document.write( "There's more than one way to go at this, but you get the same answer.
\n" ); document.write( "a/bx = e - c/d
\n" ); document.write( "a/bx = (de-c)/d
\n" ); document.write( "Invert
\n" ); document.write( "bx/a = d/(de-c)
\n" ); document.write( "bx = ad/(de-c)
\n" ); document.write( "\"x+=+ad%2F%28b%2A%28de-c%29%29\"
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