document.write( "Question 148397: Here's a hard one...HELP\r
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document.write( "In 1991, th elife expectancy of males in a certain country was 70.4 years. In 1998, it was 74.2 years. Let E represent the life expectancy in year t and let t represent the number of years since 1991.\r
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document.write( "The linear function E(t) that fits the data is??\r
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document.write( "E(t) = ??t + ??
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document.write( "(round to the nearest tenth)
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document.write( "Use the function to predict the life expectancy of males in 2003.
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document.write( "E(12)=???
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document.write( "(round to the nearest tenth)
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Algebra.Com's Answer #108769 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! In 1991, the life expectancy of males in a certain country was 70.4 years. \n" ); document.write( "In 1998, it was 74.2 years. \n" ); document.write( "Let E represent the life expectancy in year t and let t represent the number of years since 1991 \n" ); document.write( "----------- \n" ); document.write( "You have two points relating t and E: (0,70.4) and (7,74.2) \n" ); document.write( "slope = (74.2-70.4)/7 = 3.8/7 = 19/35 \n" ); document.write( "intercept: 70.4 \n" ); document.write( "------------------------ \n" ); document.write( "The linear function E(t) that fits the data is?? \n" ); document.write( "E(t) =(19/35)t + 70.4 \n" ); document.write( "(round to the nearest tenth)\r \n" ); document.write( "\n" ); document.write( "Use the function to predict the life expectancy of males in 2003. \n" ); document.write( "E(12)= (19/35)*12 + 70.4 = 76.9 years \n" ); document.write( "(round to the nearest tenth) \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |