document.write( "Question 148405: 24. From the list of plotted points
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\n" ); document.write( "(-5,5) (3,5)
\n" ); document.write( "(-4, 3/2) (2, 3/2)
\n" ); document.write( "(-3,-1) (1,-1)
\n" ); document.write( "(-2, -5/2) (0, -5/2)
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\n" ); document.write( "Form an equation after plotting these points and then answer the questions below:\r
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\n" ); document.write( "\n" ); document.write( "Is the leading coefficient of the polynomial positive or negative? \r
\n" ); document.write( "\n" ); document.write( "Number of zeros
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Algebra.Com's Answer #108758 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If we plot the points we get\r
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\n" ); document.write( "\n" ); document.write( "Now draw a curve through these points to get the equation:\r
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\n" ); document.write( "\n" ); document.write( "\"Photobucket\r
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\n" ); document.write( "\n" ); document.write( "From the graph, we can see that the degree is even (since both ends of the graph go in the same y direction). Also, we can see that the leading coefficient is positive (since the graph opens upward). Finally, we can see that there are two zeros (since there are two x-intercepts).\r
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\n" ); document.write( "\n" ); document.write( "Since we have all of this info, we don't need the equation. However, if you do need the equation, this is how you would find it:\r
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\n" ); document.write( "\n" ); document.write( "From the graph, we can see that the vertex is (-1,-3). \r
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\n" ); document.write( "\n" ); document.write( "\"y=a%28x-h%29%5E2%2Bk\" Start with the general vertex equation.\r
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\n" ); document.write( "\n" ); document.write( "\"y=a%28x--1%29%5E2-3\" Plug in \"h=-1\" and \"k=-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=a%28x%2B1%29%5E2-3\" Simplify.\r
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\n" ); document.write( "\n" ); document.write( "Now let's plug in another point. Let's plug in (1,-1)\r
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\n" ); document.write( "\n" ); document.write( "\"-1=a%281%2B1%29%5E2-3\" Plug in \"x=1\" and \"y=-1\"\r
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\n" ); document.write( "\n" ); document.write( "\"-1=a%282%29%5E2-3\" Add\r
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\n" ); document.write( "\n" ); document.write( "\"-1=4a-3\" Square 2 to get 4.\r
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\n" ); document.write( "\n" ); document.write( "\"0=4a-3%2B1\" Add \"1\" to both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-4a=-3%2B1\" Subtract \"4a\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-4a=-2\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"a=%28-2%29%2F%28-4%29\" Divide both sides by \"-4\" to isolate \"a\".\r
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\n" ); document.write( "\n" ); document.write( "\"a=1%2F2\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So this means that the equation is \"y=%281%2F2%29%28x%2B1%29%5E2-3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F2%29%28x%5E2%2B2x%2B1%29-3\" FOIL\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F2%29x%5E2%2B%281%2F2%292x%2B%281%2F2%291-3\" Distribute\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F2%29x%5E2%2Bx%2B1%2F2-3\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"y=%281%2F2%29x%5E2%2Bx-5%2F2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "So the equation that goes through the points is \"y=%281%2F2%29x%5E2%2Bx-5%2F2\" \r
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\n" ); document.write( "\n" ); document.write( "From the equation, we can see that the degree of the polynomial is even. Also, we can see that the leading coefficient is positive since \"a=1%2F2\". Finally, if we use the quadratic formula, we'll find that the polynomial \"y=%281%2F2%29x%5E2%2Bx-5%2F2\" has 2 zeros.\r
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