document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22384>Question 22384</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Explain each step involved in using the 'ac' method to factor the following: \r<BR>\n" );
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document.write( "5w^2 + 13w - 6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10872 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10872\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ac = 5*-6=-30<BR>\n" );
document.write( "b  = 13<BR>\n" );
document.write( "Determine two integers whose product is -30 and whose sum is 13.<BR>\n" );
document.write( "They are 15 and -2<BR>\n" );
document.write( "Rewrite the original equation putting 15w-2w in place of 13w as follows.<BR>\n" );
document.write( "5w^2 +15w-2w-6<BR>\n" );
document.write( "Factor the 1st two then the last two terms as follows:<BR>\n" );
document.write( "5w(w+3)-2(w+6)<BR>\n" );
document.write( "Factor again to get:<BR>\n" );
document.write( "(w+3)(5x-2)\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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