document.write( "Question 148298: find x:\r
\n" ); document.write( "\n" ); document.write( "2 sqrt of x-3 = 12 \n" ); document.write( "
Algebra.Com's Answer #108717 by nerdybill(7384)\"\" \"About 
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2 sqrt(x-3) = 12
\n" ); document.write( "Begin by dividing both sides by 2:
\n" ); document.write( "sqrt(x-3) = 6
\n" ); document.write( "Now, square both sides:
\n" ); document.write( "x-3 = 36
\n" ); document.write( "Finally, add 3 to both sides:
\n" ); document.write( "x = 39
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\n" ); document.write( "To check, plug it back in to the original equation:
\n" ); document.write( "2 sqrt(x-3) = 12
\n" ); document.write( "2 sqrt(39-3) = 12
\n" ); document.write( "2 sqrt(36) = 12
\n" ); document.write( "2(6) = 12
\n" ); document.write( "12 = 12 (checks) \n" ); document.write( "
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