document.write( "Question 148322: Find the value of x in logx + 1/logx = 5/2 \n" ); document.write( "
Algebra.Com's Answer #108713 by stanbon(75887)\"\" \"About 
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Find the value of x in logx + 1/logx = 5/2\r
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\n" ); document.write( "Multiply thru by 2logx to get:
\n" ); document.write( "2(logx)^2 + 2 = 5logx
\n" ); document.write( "Rearrange:
\n" ); document.write( "2(logx)^2 - 5logx + 2 = 0
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\n" ); document.write( "This is a quadratic with variable logx:
\n" ); document.write( "Let logx = w and substitute:
\n" ); document.write( "2w^2 -5w + 2 = 0
\n" ); document.write( "Factor using the AC Method:
\n" ); document.write( "2w^2-4w-w+2 = 0
\n" ); document.write( "2w(w-2)-(w-2) = 0
\n" ); document.write( "(w-2)(2w-1) = 0
\n" ); document.write( "w = 2 or w = 1/2
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\n" ); document.write( "Substiute back to logx:
\n" ); document.write( "logx = 2 or logx = 1/2
\n" ); document.write( "x = 10^2 or x = 10^(1/2)
\n" ); document.write( "x = 100 or x = sqrt(10)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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