document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=148088>Question 148088</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The maximum value of z = 20x + 8y subject to:\r<BR>\n" );
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document.write( "3x + y &#8804; 24<BR>\n" );
document.write( "6x + 4y &#8804; 66<BR>\n" );
document.write( "x &#8805; 0, y &#8805; 0 \r<BR>\n" );
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document.write( "a. 220<BR>\n" );
document.write( "b. 160<BR>\n" );
document.write( "c. 172<BR>\n" );
document.write( "d. 132 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #108710 by </B><A HREF=/tutors/aboutme.mpl?userid=nabla><B>nabla(475)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nabla><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=108710\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the auxiliaries for y first.\r<BR>\n" );
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document.write( "y<=24-3x<BR>\n" );
document.write( "y<=33/2 -3x/2\r<BR>\n" );
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document.write( "Now, if y>=0,<BR>\n" );
document.write( "24-3x >=0<BR>\n" );
document.write( "33/2 - 3x/2 >=0\r<BR>\n" );
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document.write( "Moreover,<BR>\n" );
document.write( "if x>=0, <BR>\n" );
document.write( "-3x>=-24<BR>\n" );
document.write( "-3x/2>=-33/2\r<BR>\n" );
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document.write( "Even further,<BR>\n" );
document.write( "x<=8<BR>\n" );
document.write( "x<=11\r<BR>\n" );
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document.write( "So the maximum of x will be 8. \r<BR>\n" );
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document.write( "Now, <BR>\n" );
document.write( "y<=0 follows from the first condition with restriction x<=8. So the maximum of y will be 0.\r<BR>\n" );
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document.write( "Thus,<BR>\n" );
document.write( "z=20x + 8y\r<BR>\n" );
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document.write( "z=20*11=220\r<BR>\n" );
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document.write( "Which is answer (a). </SPAN>\n" );
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