document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22389>Question 22389</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hello, can you help with the following formula\r<BR>\n" );
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document.write( "Given y=x^(1/(p-1))<BR>\n" );
document.write( "Calculate P if y =2.65 and x = 0.745\r<BR>\n" );
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document.write( "Many thanks  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10871 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10871\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Take the log of both sides of the equation to get the \"x\" out of the exponent.\r<BR>\n" );
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document.write( "log y = (1/(p-1))log x\r<BR>\n" );
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document.write( "Then divide both sides by log x to get:<BR>\n" );
document.write( "   (logy)/(logx) = 1/(p-1)<BR>\n" );
document.write( "Invert both sides to get:<BR>\n" );
document.write( "p-1 = (logx)/(logy)\r<BR>\n" );
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document.write( "p = (logx)/(logy)-1<BR>\n" );
document.write( "Substitute to get:<BR>\n" );
document.write( "p= (log0.745)/(log2.65) -1<BR>\n" );
document.write( "p=-1.30\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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