document.write( "Question 148307: Write in standard form: (3-2i)^2 \n" ); document.write( "
Algebra.Com's Answer #108706 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"%283-2i%29%5E2\" Start with the given expression.\r
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\n" ); document.write( "\n" ); document.write( "\"%283-2i%29%283-2i%29\" Expand. Remember something like \"x%5E2=x%2Ax\".\r
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\n" ); document.write( "\n" ); document.write( "Now let's FOIL the expression.\r
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\n" ); document.write( "\n" ); document.write( "Remember, when you FOIL an expression, you follow this procedure:\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%283%29-2i%29%28highlight%283%29-2i%29\" Multiply the First terms:\"%283%29%2A%283%29=9\".\r
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\n" ); document.write( "\n" ); document.write( "\"%28highlight%283%29-2i%29%283%2Bhighlight%28-2i%29%29\" Multiply the Outer terms:\"%283%29%2A%28-2%2Ai%29=-6%2Ai\".\r
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\n" ); document.write( "\n" ); document.write( "\"%283%2Bhighlight%28-2i%29%29%28highlight%283%29-2i%29\" Multiply the Inner terms:\"%28-2%2Ai%29%2A%283%29=-6%2Ai\".\r
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\n" ); document.write( "\n" ); document.write( "\"%283%2Bhighlight%28-2i%29%29%283%2Bhighlight%28-2i%29%29\" Multiply the Last terms:\"%28-2%2Ai%29%2A%28-2%2Ai%29=4%2Ai%5E2=4%28-1%29=-4\".\r
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\n" ); document.write( "\n" ); document.write( "\"9-6%2Ai-6%2Ai-4\" Now collect every term to make a single expression.\r
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\n" ); document.write( "\n" ); document.write( "\"5-12%2Ai\" Now combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Now the number is in standard form a+bi where a=5 and b=-12
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