document.write( "Question 148306: Solve 4x^2+20=0
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Algebra.Com's Answer #108705 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"4x%5E2%2B20=0\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"4x%5E2=0-20\" Subtract \"20\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"4x%5E2=-20\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=%28-20%29%2F%284%29\" Divide both sides by \"4\" to isolate \"x%5E2\".\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=-5\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"x=0%2B-sqrt%28-5%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%28-5%29\" or \"x=-sqrt%28-5%29\" Break up the expression.\r
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\n" ); document.write( "\n" ); document.write( "\"x=i%2Asqrt%285%29\" or \"x=-i%2Asqrt%285%29\" Simplify the square root.\r
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\n" ); document.write( "\n" ); document.write( "So our answers are \"x=i%2Asqrt%285%29\" or \"x=-i%2Asqrt%285%29\"\r
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