document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=148291>Question 148291</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How many ways can a baseball coach choose the first, second and third batters in the lineup of a team of 15 players. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #108684 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=108684\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> For the 1st, he can choose any of 15<BR>\n" );
document.write( "For the 2nd, any of the remaining 14<BR>\n" );
document.write( "For the 3rd, any of the remaining 13<BR>\n" );
document.write( "So for the 1st, there are 15 choices, then 14, then 13.<BR>\n" );
document.write( "# of combinations = 15*14*13 = 2,730. </SPAN>\n" );
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