document.write( "Question 148282: Trains A and B are traveling in the same direction on parallel lines. Train A is traveling at 40 miles per hour and Train B is traveling 50 miles an hour. Than Train A passes a station at 12:25 PM. If Train B passes the same station at 12:35 PM. What time will B catch up with Train A? When will Train B catch up with Train A?
\n" ); document.write( "When will Train B catch up to Train A?\r
\n" ); document.write( "\n" ); document.write( "Time ??? PM or AM?\r
\n" ); document.write( "\n" ); document.write( "Thanks
\n" ); document.write( "

Algebra.Com's Answer #108680 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Imagine that I am a passenger on train B. I have a stopwatch and a very
\n" ); document.write( "accurate clock too. I've got a cell phone and I'm in contact with
\n" ); document.write( "someone at the station
\n" ); document.write( "I know the seed of train A and train B also.
\n" ); document.write( "I tell the station \"Let me know exactly when train A passes the station\"
\n" ); document.write( "They tell me \"Train A just passed\"
\n" ); document.write( "My clock tells me it's 12:25
\n" ); document.write( "Then my train, train B, passes the station.
\n" ); document.write( "My clock says it's 12:35. I start my stopwatch
\n" ); document.write( "10 minutes have passed, or \"10%2F60\"of an hour and since \"d+=+r%2At\"
\n" ); document.write( "\"d+=+40%2A%2810%2F60%29\"
\n" ); document.write( "\"d+=+40%2F6\"mi
\n" ); document.write( "That's how far train A is from the station when I go past the station.
\n" ); document.write( "I know train A is \"40%2F6\" mi ahead of me, but when I stop the
\n" ); document.write( "stopwatch we will be side by side.
\n" ); document.write( "Let \"t\" = time from start to stop
\n" ); document.write( "\"d\" = the distance I have to go to meet train A
\n" ); document.write( "\"d+-+40%2F6\" is the distance train A has to go to meet me
\n" ); document.write( "For A:
\n" ); document.write( "\"d+-+%2840%2F6%29+=+40t\"
\n" ); document.write( "For B:
\n" ); document.write( "\"d+=+50t\"
\n" ); document.write( "Substitute the 2nd equation into the 1st
\n" ); document.write( "\"50t+-+%2840%2F6%29+=+40t\"
\n" ); document.write( "multiply both sides by \"6\"
\n" ); document.write( "\"300t+-+40+=+240t\"
\n" ); document.write( "\"60t+=+40\"
\n" ); document.write( "\"t+=+40%2F60\" hr or \"40\" min
\n" ); document.write( "If I started my stopwatch at 12:35 PM, then the trains meet
\n" ); document.write( "at 1:15 PM answer
\n" ); document.write( "check answer:
\n" ); document.write( "\"d+=+50t\"
\n" ); document.write( "\"d+=+50%2A%2840%2F60%29\"
\n" ); document.write( "\"d+=+100%2F3\" mi
\n" ); document.write( "Train A covers this distance (station to meeting) in
\n" ); document.write( "\"10%2F60+%2B+40%2F60+=+50%2F60\" hr
\n" ); document.write( "\"d%5BA%5D+=+r%5BA%5D%2At\"
\n" ); document.write( "\"100%2F3+=+40%2A%2850%2F60%29\"
\n" ); document.write( "\"100+=+120%2A%285%2F6%29\"
\n" ); document.write( "\"600+=+120%2A5\"
\n" ); document.write( "\"600+=+600\"
\n" ); document.write( "OK
\n" ); document.write( "
\n" );