document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22398>Question 22398</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Mary is \"y\" years old. Her father is 4 times older than Mary. Her mother is 7 years younger than her father. If the three ages add up to 101 years, find the value of \"y\". Find the ages of Mary's parents.\r<BR>\n" );
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document.write( "Thanks in advance! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10866 by </B><A HREF=/tutors/aboutme.mpl?userid=elima><B>elima(1433)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=elima><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10866\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Mary = y<BR>\n" );
document.write( "Her father = 4y<BR>\n" );
document.write( "Her mother = 4y-7<BR>\n" );
document.write( "y+4y+4y-7=101<BR>\n" );
document.write( "9y-7=101<BR>\n" );
document.write( "9y=108<BR>\n" );
document.write( "y=12<BR>\n" );
document.write( "So Mary's age is 12, her father would be 4(12)=48, <BR>\n" );
document.write( "Her maother would be 4(12)-7=48-7=41<BR>\n" );
document.write( "Hope you understand<BR>\n" );
document.write( "=) </SPAN>\n" );
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