document.write( "Question 148235: My car gets 12 miles per gallon of gasolene. Gas is 4$/gallon.
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document.write( "If I buy a car that gets 16 miles per gallon at a cost of $500, how long or how many miles will it take me to pay for it with savings of gas cost?\r
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document.write( "Help please,
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document.write( "Bob \n" );
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Algebra.Com's Answer #108643 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! My car gets 12 miles per gallon of gasoline. Gas is 4$/gallon. \n" ); document.write( "If I buy a car that gets 16 miles per gallon at a cost of $500, how long or how many miles will it take me to pay for it with savings of gas cost? \n" ); document.write( ": \n" ); document.write( "Let x = no. of miles to recover $500 \n" ); document.write( ": \n" ); document.write( "Cost to drive old car: 4(x/12) \n" ); document.write( "Cost to drive new car: 4(x/16) \n" ); document.write( ": \n" ); document.write( "Old car cost - new car cost = $500 \n" ); document.write( " \n" ); document.write( "Cancel the 4's \n" ); document.write( " \n" ); document.write( "Multiply equation by 12; gets rid of the denominator and you have \n" ); document.write( "4x - 3x = 12(500) \n" ); document.write( "; \n" ); document.write( "x = 6000 mi to recover the $500 spent (Lose the $ sign) \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution: \n" ); document.write( "4(6000/12) - 4(6000/16) = \n" ); document.write( " 2000 - 1500 = 500 \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |