document.write( "Question 148202: Verify the identity.\r
\n" ); document.write( "\n" ); document.write( "a)(csc(-t)-sin(-t))/(sin(-t))=cot^(2)t\r
\n" ); document.write( "\n" ); document.write( "b)ln cotx= -ln tanx
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Algebra.Com's Answer #108604 by mangopeeler07(462)\"\" \"About 
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a)(csc(-t)-sin(-t))/(sin(-t))=cot^(2)t\r
\n" ); document.write( "\n" ); document.write( "Kick out those t's to make this thing look better.\r
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\n" ); document.write( "\n" ); document.write( "(csc-sin)/(sin)=cot^2\r
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\n" ); document.write( "\n" ); document.write( "Plug in identities you already know.\r
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\n" ); document.write( "\n" ); document.write( "cot^2=cos^2/sin^2
\n" ); document.write( "csc=1/sin\r
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\n" ); document.write( "\n" ); document.write( "(1/sin)-sin/sin)=cos^2/sin^2\r
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\n" ); document.write( "\n" ); document.write( "Do 1/sin-sin.\r
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\n" ); document.write( "\n" ); document.write( "(1/sin)-sin=(1/sin)-(sin^2/sin) or (1-sin^2)/sin\r
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\n" ); document.write( "\n" ); document.write( "1-sin^2=cos^2
\n" ); document.write( "So (1-sin^2)/sin = cos^2/sin.\r
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\n" ); document.write( "\n" ); document.write( "Plug that back into ((1/sin)-sin)/sin=cos^2/sin^2\r
\n" ); document.write( "\n" ); document.write( "and get (cos^2/sin)/sin=cos^2/sin^2\r
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\n" ); document.write( "\n" ); document.write( "Change (cos^2/sin)/sin to (cos^2/sin)(1/sin) and get cos^2/sin^2, or cot^2.
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