document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2539>Question 2539</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 8x^2-x-7\r<BR>\n" );
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document.write( "THANK YOU!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1086 by </B><A HREF=/tutors/aboutme.mpl?userid=kiru_khandelwal><B>kiru_khandelwal(79)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kiru_khandelwal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1086\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in a quadratic equation\r<BR>\n" );
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document.write( "ax^2+bx+c = 0<BR>\n" );
document.write( "x = (-b + sqrt(b^2-4ac))/2a and (-b - sqrt(b^2-4ac))/2a\r<BR>\n" );
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document.write( "so for the quadratic equation<BR>\n" );
document.write( "8x^2-x-7 \r<BR>\n" );
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document.write( "a=8, b=-1, c=-7\r<BR>\n" );
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document.write( "therefore, x = (-(-1) + sqrt((-1)^2 - 4*8*(-7)))/2*8 = (1+sqrt(225))/16 =(1+15)/16=1\r<BR>\n" );
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document.write( "and also <BR>\n" );
document.write( "x =  (-(-1) - sqrt((-1)^2 - 4*8*(-7)))/2*8 = (1-sqrt(225))/16 =(1-15)/16=-14/16 = -7/8\r<BR>\n" );
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document.write( "so x = 1, -7/8 </SPAN>\n" );
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