document.write( "Question 148192: (3x^3y^3)/xy=?
\n" );
document.write( "x and y equal 0 \n" );
document.write( "
Algebra.Com's Answer #108586 by mangopeeler07(462)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "where \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If x and y are zero, and they are both in the denominator, then this is undefined, because division by zero is undefined. Why? Get this:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "12 divided by 3 is 4, right? Because 4 times 3 is 12.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "14 divided by 2 is 7, right? Because 7 times 2 is 14.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "25 divided by 5 is 5, right? because 5 times 5 is 25.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "4 divided by 0 is 0, right? Because 0 times 0 is...(?!).\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "That is why anything besides zero over zero is an undefined value. \n" ); document.write( " |