document.write( "Question 148190: Graph and Solve:\r
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Algebra.Com's Answer #108584 by mangopeeler07(462)\"\" \"About 
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equation: y=3x-5
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\n" ); document.write( "\n" ); document.write( "The y intercept and the slope are given in the equation. y=mx+b is slope-intercept form. mx is the slope and b is the y intercept. so in y=3x-5, 3x is the slope and -5 is the y intercept (what y is when x is zero).\r
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\n" ); document.write( "\n" ); document.write( "equation: y=3x-5
\n" ); document.write( "3points: ?
\n" ); document.write( "Slope: 3x
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\n" ); document.write( "\n" ); document.write( "To find the x intercept, find what x is when y is zero. That means take the original equation and plug in zero for y. Like so: 0=3x-5. Then solve for x and get 5/3. That is the x intercept.\r
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\n" ); document.write( "\n" ); document.write( "equation: y=3x-5
\n" ); document.write( "3points: ?
\n" ); document.write( "Slope: 3x
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\n" ); document.write( "\n" ); document.write( "To find three points, plug in another value for x. You already have two points, the y-intercept (0,-5) and the x-intercept (5/3,0). Plug in one more value for x or y. How about x=3? y=3(3)-5 or y=9-5. y=4. So your third point would be (3,4)\r
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\n" ); document.write( "\n" ); document.write( "equation: y=3x-5
\n" ); document.write( "3points: (0,-5) (5/3,0) (3,4)
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Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc
Equation \"-3+x+%2B+1+y+=+-5\" describes a sloping line. For any
\n" ); document.write( " equation ax+by+c = 0, slope is \"-a%2Fb+=+--3%2F1\".
  • X intercept is found by setting y to 0: ax+by=c becomes ax=c. that means that x = c/a. -5/-3 = 1.66666666666667.
  • Y intercept is found by setting x to 0: the equation becomes by=c, and therefore y = c/b. Y intercept is -5/1 = -5.
  • Slope is --3/1 = 3.
  • Equation in slope-intercept form: y=3*x+-5.
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