document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=148149>Question 148149</A>: <I><SPAN STYLE=\"word-break: break-all;\"> rectangle ABCD has AB = 16 and BC = 6. Let M be the midpoint of side AD and N be the midpoint of side CD. Segments CM and An intersect at G. Find the length AG.\r<BR>\n" );
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document.write( "I did this on the geometer's sketchpad and i got 6.66748, but i don't understand how to do it by hand. Thanks for the help!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #108552 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=108552\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> put the rectangle on a coordinate system\r<BR>\n" );
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document.write( "D is the origin (0,0) __ AD runs up the y-axis and DC goes along the x-axis\r<BR>\n" );
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document.write( "the equation for AN is y=(-3/4)x+6 __ the equation for CM is y=(-3/16)x+3\r<BR>\n" );
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document.write( "for G (the intersection) (-3/4)x+6=(-3/16)x+3 __ adding 3x/4 and -3 __ 3=(9/16)x __ dividing by 9/16 __ 16/3=x\r<BR>\n" );
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document.write( "substituting to find y __ y=(-3/16)(16/3)+3 __ y=-1+3 __ y=2\r<BR>\n" );
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document.write( "so the coordinates of G are (16/3,2)\r<BR>\n" );
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document.write( "using the distance formula __ (AG)^2=(16/3)^2 + (6-2)^2 __ AG^2=256/9+16 __ AG^2=256/9+144/9 __ AG^2=400/9 __ AG=20/3 </SPAN>\n" );
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