document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=148138>Question 148138</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0764119729/algebrahomeworkh>algebra: the easy way</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> 41: 4(3+x)+10= -11(x-6)+1 <BR>\n" );
document.write( "43:3x+21=-2x+11<BR>\n" );
document.write( "45:6x+4=2x\r<BR>\n" );
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document.write( "whenever i experiance any of these types of questions im not sure how to solve for x when there is an x on both sides of the equation. Given that the book that im using does not go over how to do these types of equations im at lost of how to do it, any help trying to solve these equations is greatly appreciated by me, thank you.<BR>\n" );
document.write( "-Brian. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #108550 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=108550\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Just follow the basic rules of algebra to get the variable (x) on one side by itself\r<BR>\n" );
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document.write( "41: <BR>\n" );
document.write( "4(3+x)+10 = -11(x-6) + 1<BR>\n" );
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document.write( "Multiply what's inside the brackets:<BR>\n" );
document.write( "12 + 4x + 10 = -11x + 66 + 1<BR>\n" );
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document.write( "4x + 22 = -11x + 67<BR>\n" );
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document.write( "Add 11x to both sides, that eliminates -11x on the right<BR>\n" );
document.write( "4x + 11x + 22 = 67<BR>\n" );
document.write( "15x + 22 = 67<BR>\n" );
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document.write( "Subtract 22 from both sides, that eliminates 22 on the left<BR>\n" );
document.write( "15x = 67 - 22<BR>\n" );
document.write( "15x = 45<BR>\n" );
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document.write( "Divide both sides by 15, that leaves just x on the left<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=45%2F15 ALIGN=MIDDLE  ALT=\"45%2F15\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 3<BR>\n" );
document.write( "I leave it up to you to confirm these solutions, in this one substitute 3 for x in the original equation<BR>\n" );
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document.write( "43:<BR>\n" );
document.write( "3x + 21 = -2x + 11<BR>\n" );
document.write( "Follow the same rules<BR>\n" );
document.write( "3x + 2x = 11 - 21<BR>\n" );
document.write( "5x = -10<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-10%29%2F5 ALIGN=MIDDLE  ALT=\"%28-10%29%2F5\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = -2<BR>\n" );
document.write( "Check this solution the same way<BR>\n" );
document.write( ":<BR>\n" );
document.write( "45:<BR>\n" );
document.write( "6x + 4 = 2x<BR>\n" );
document.write( "6x - 2x = -4<BR>\n" );
document.write( "4x = -4<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-4%29%2F4 ALIGN=MIDDLE  ALT=\"%28-4%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = -1<BR>\n" );
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document.write( "Are you getting the idea now?  </SPAN>\n" );
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