document.write( "Question 148112: The Product of two consecutive positive intergers is 1 more than their sum. Find the intergers. \n" ); document.write( "
Algebra.Com's Answer #108509 by Electrified_Levi(103)\"\" \"About 
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Hi, Hope I can help,
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\n" ); document.write( "The Product of two consecutive positive integers is 1 more than their sum. Find the integers.
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\n" ); document.write( "The first integer is \"x\", the second is (x+1)
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\n" ); document.write( "consecutive means one after the other, if there was a third, fourth, and fifth integer it would be (x+2),(x+3),(x+4)(You will do this on any problem where it says consecutive(unless it says consecutive odd, or even, then you add \"2\" each time
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\n" ); document.write( "Now we can do the equation
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\n" ); document.write( "The Product of two consecutive positive integers is 1 more than their sum.
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\n" ); document.write( "(x)(x+1) = (x)+(x+1)+1
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\n" ); document.write( "We will use the distributive property
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\n" ); document.write( "\"+x%5E2%2Bx+=+%28x%29%2B%28x%2B1%29%2B1+\"
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\n" ); document.write( "\"+x%5E2%2Bx+=+x%2Bx%2B1%2B1+\"
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\n" ); document.write( "\"+x%5E2%2Bx+=+2x%2B2+\"
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\n" ); document.write( "We will move everything on the left side
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\n" ); document.write( "\"+x%5E2%2Bx+-+2x+-2+=+2x+-2x%2B2-2+\"
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\n" ); document.write( "\"+x%5E2+-+x+-+2+=+0+\"
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\n" ); document.write( "\"+x%5E2+-+x+-+2+\" has factors of (x+1), and (x-2) ( factors of (-2) add up to (-1))
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\n" ); document.write( "We can now solve for \"x\", using one factor at a time.
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\n" ); document.write( "First factor
\n" ); document.write( "(x+1)=0
\n" ); document.write( "x+1=0
\n" ); document.write( "x+1-1=0-1
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\n" ); document.write( "x=(-1)
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\n" ); document.write( "Second factor
\n" ); document.write( "(x-2)=0
\n" ); document.write( "x-2=0
\n" ); document.write( "x-2+2=0+2
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\n" ); document.write( "x = 2
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\n" ); document.write( "You can check by replacing \"x\" with (-1), or 2, in the equation
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\n" ); document.write( "\"+x%5E2+-+x+-+2+=+0+\" ( We will only check one answer, (2)
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\n" ); document.write( "\"+2%5E2+-+2+-+2+=+0+\"
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\n" ); document.write( "\"+4+-+2+-+2+=+0+\"
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\n" ); document.write( "\"+0+=+0+\"
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\n" ); document.write( "The first integer is x, or 2(It asked for a positive integer), the second integer is (x+1), or 3
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\n" ); document.write( "You can check by replacing \"x\" with 2 in
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\n" ); document.write( "(x)(x+1) = (x)+(x+1)+1
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\n" ); document.write( "(2)(2+1) = (2)+(2+1)+1
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\n" ); document.write( "(2)(3) = (2)+(3)+1
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\n" ); document.write( "6 = 6
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\n" ); document.write( "First integer = 2
\n" ); document.write( "Second integer = 3
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\n" ); document.write( "Hope I helped, Levi
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