document.write( "Question 148112: The Product of two consecutive positive intergers is 1 more than their sum. Find the intergers. \n" ); document.write( "
Algebra.Com's Answer #108509 by Electrified_Levi(103)![]() ![]() ![]() You can put this solution on YOUR website! Hi, Hope I can help, \n" ); document.write( ". \n" ); document.write( "The Product of two consecutive positive integers is 1 more than their sum. Find the integers. \n" ); document.write( ". \n" ); document.write( "The first integer is \"x\", the second is (x+1) \n" ); document.write( ". \n" ); document.write( "consecutive means one after the other, if there was a third, fourth, and fifth integer it would be (x+2),(x+3),(x+4)(You will do this on any problem where it says consecutive(unless it says consecutive odd, or even, then you add \"2\" each time \n" ); document.write( ". \n" ); document.write( "Now we can do the equation \n" ); document.write( ". \n" ); document.write( "The Product of two consecutive positive integers is 1 more than their sum. \n" ); document.write( ". \n" ); document.write( "(x)(x+1) = (x)+(x+1)+1 \n" ); document.write( ". \n" ); document.write( "We will use the distributive property \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "We will move everything on the left side \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "We can now solve for \"x\", using one factor at a time. \n" ); document.write( ". \n" ); document.write( "First factor \n" ); document.write( "(x+1)=0 \n" ); document.write( "x+1=0 \n" ); document.write( "x+1-1=0-1 \n" ); document.write( ". \n" ); document.write( "x=(-1) \n" ); document.write( ". \n" ); document.write( "Second factor \n" ); document.write( "(x-2)=0 \n" ); document.write( "x-2=0 \n" ); document.write( "x-2+2=0+2 \n" ); document.write( ". \n" ); document.write( "x = 2 \n" ); document.write( ". \n" ); document.write( "You can check by replacing \"x\" with (-1), or 2, in the equation \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "The first integer is x, or 2(It asked for a positive integer), the second integer is (x+1), or 3 \n" ); document.write( ". \n" ); document.write( "You can check by replacing \"x\" with 2 in \n" ); document.write( ". \n" ); document.write( "(x)(x+1) = (x)+(x+1)+1 \n" ); document.write( ". \n" ); document.write( "(2)(2+1) = (2)+(2+1)+1 \n" ); document.write( ". \n" ); document.write( "(2)(3) = (2)+(3)+1 \n" ); document.write( ". \n" ); document.write( "6 = 6 \n" ); document.write( ". \n" ); document.write( "First integer = 2 \n" ); document.write( "Second integer = 3 \n" ); document.write( ". \n" ); document.write( "Hope I helped, Levi \n" ); document.write( " |