document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=2562>Question 2562</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the distance between each pair of points whose coordinates are given Express answers in simplest radical form and as decimal approximations to the nearest hundreth\r<BR>\n" );
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document.write( "1.(9,7),(1,1)<BR>\n" );
document.write( "2.(5,2),(8,-2)<BR>\n" );
document.write( "3.(1,-3, (1,4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1085 by </B><A HREF=/tutors/aboutme.mpl?userid=kiru_khandelwal><B>kiru_khandelwal(79)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=kiru_khandelwal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1085\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance between points with coordinates (x1,y1) and (x2,y2) is sqrt((x2-x1)*(x2-x1) + (y2-y1)*(y2-y1))\r<BR>\n" );
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document.write( "Therefore distance between<BR>\n" );
document.write( "1) (9,7),(1,1)<BR>\n" );
document.write( "=> x2-x1 = 1-9 = -8<BR>\n" );
document.write( "=> y2-y1 = 1-7 = -6<BR>\n" );
document.write( "Distance between two points = sqrt ((-8)*(-8) + (-6)*(-6))<BR>\n" );
document.write( "=> sqrt(64 + 36) => sqrt (100) => 10\r<BR>\n" );
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document.write( "Similarly distancex between other pairs can also be found out </SPAN>\n" );
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