document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=148079>Question 148079</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with these algebra questions\r<BR>\n" );
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document.write( "1.  Find the inverse of the function f(x)=8x+16\r<BR>\n" );
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document.write( "2.  Write y=x^5 in log form\r<BR>\n" );
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document.write( "3.  Write log 7 49=2 in expotonential form (log base 7 of 49 equals 2)\r<BR>\n" );
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document.write( "4.  use the change-of-base formula (log,r=log r/log a<BR>\n" );
document.write( "                                             b     b<BR>\n" );
document.write( "to solve for x: x=log3 90\r<BR>\n" );
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document.write( "5.  Solve for x: 9/(4x)+1/3=5/(2x)\r<BR>\n" );
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document.write( "6.  Sove the system of linear equations: 2x+3y=-5 and y=2x+9\r<BR>\n" );
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document.write( "I get really confuse on #4, because after looking at the formula I found in the book to say; a,b and r are positive numbers, with a=1 (with slash through middle of =) and b=1(also with slash through middle of equal sign) then the formula property log,r=log r/log a<BR>\n" );
document.write( "                          b     b<BR>\n" );
document.write( "the b is under the r and a like when putting x^2 I hope that makes sense to you.<BR>\n" );
document.write( "Thanks  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #108469 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=108469\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1. Find the inverse of the function f(x)=8x+16<BR>\n" );
document.write( "Interchange x and y to get:<BR>\n" );
document.write( "x = 8y + 16<BR>\n" );
document.write( "Solve for y<BR>\n" );
document.write( "y = (-1/*)x - 2<BR>\n" );
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document.write( "2. Write y=x^5 in log form <BR>\n" );
document.write( "log(base x) y = 5<BR>\n" );
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document.write( "3. Write log 7 49=2 in exponential form <BR>\n" );
document.write( "7^2 = 49<BR>\n" );
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document.write( "4. use the change-of-base formula (log,r=log r/log a<BR>\n" );
document.write( "b b to solve for x: x=log3 90 <BR>\n" );
document.write( "x = [log 90]/[log 3]<BR>\n" );
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document.write( "5. Solve for x: 9/(4x)+1/3=5/(2x)<BR>\n" );
document.write( "Multiply thru by 12x to get:<BR>\n" );
document.write( "27 + 4x = 30<BR>\n" );
document.write( "4x = 3<BR>\n" );
document.write( "x = 3/4<BR>\n" );
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document.write( "6. Solve the system of linear equations: 2x+3y=-5 and y=2x+9 <BR>\n" );
document.write( "Substitute to solve for \"x\":<BR>\n" );
document.write( "2x + 3(2x+9) =9<BR>\n" );
document.write( "8x + 27 = 9<BR>\n" );
document.write( "8x = -28<BR>\n" );
document.write( "x = -19/4<BR>\n" );
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document.write( "Substitute into y = 2x+9 to solve for \"y\":<BR>\n" );
document.write( "y = 2(-19/4)+9<BR>\n" );
document.write( "y = -39/4 + 36/4<BR>\n" );
document.write( "y = -3/4<BR>\n" );
document.write( "=============<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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