document.write( "Question 148066: I need this solved using a proportion\r
\n" ); document.write( "\n" ); document.write( "A truck can pump 800 gallons of oil in 35 minutes. How much oil can it pump in 2 hours?
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Algebra.Com's Answer #108458 by nerdybill(7384)\"\" \"About 
You can put this solution on YOUR website!
A truck can pump 800 gallons of oil in 35 minutes. How much oil can it pump in 2 hours?
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\n" ); document.write( "From:\"A truck can pump 800 gallons of oil in 35 minutes.\" we get the proportion:
\n" ); document.write( "800/35
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\n" ); document.write( "Since the above proportion is in \"minutes\" we must convert 2 hours into minutes:
\n" ); document.write( "2 hours = 120 mins
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\n" ); document.write( "Therefore, your final proportion to solve is:
\n" ); document.write( "If x = oil pumped in 2 hours
\n" ); document.write( "then
\n" ); document.write( "800/35 = x/120
\n" ); document.write( "(800/35)120 = x
\n" ); document.write( "2742.857 gallons = x
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