document.write( "Question 148066: I need this solved using a proportion\r
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document.write( "A truck can pump 800 gallons of oil in 35 minutes. How much oil can it pump in 2 hours? \n" );
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Algebra.Com's Answer #108458 by nerdybill(7384) You can put this solution on YOUR website! A truck can pump 800 gallons of oil in 35 minutes. How much oil can it pump in 2 hours? \n" ); document.write( ". \n" ); document.write( "From:\"A truck can pump 800 gallons of oil in 35 minutes.\" we get the proportion: \n" ); document.write( "800/35 \n" ); document.write( ". \n" ); document.write( "Since the above proportion is in \"minutes\" we must convert 2 hours into minutes: \n" ); document.write( "2 hours = 120 mins \n" ); document.write( ". \n" ); document.write( "Therefore, your final proportion to solve is: \n" ); document.write( "If x = oil pumped in 2 hours \n" ); document.write( "then \n" ); document.write( "800/35 = x/120 \n" ); document.write( "(800/35)120 = x \n" ); document.write( "2742.857 gallons = x \n" ); document.write( " |