document.write( "Question 147483: Draw a triangle ABC, and let AM and BN be two of its medians, which intersect at G. Extend AM to the point P that makes GM = MP. Prove that PBGC is a parallelogram. \n" ); document.write( "
Algebra.Com's Answer #108440 by orca(409)\"\" \"About 
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PROOF\r
\n" ); document.write( "\n" ); document.write( "As GM = MP, BM = MC and < BMG = < PMC, triangles BMG and PMC are congruent.
\n" ); document.write( "So < GBM = < MCP.
\n" ); document.write( "Thus BG is parallel to PC.\r
\n" ); document.write( "\n" ); document.write( "Similarly, we can show that GC is parallel to BP.\r
\n" ); document.write( "\n" ); document.write( "So PBGC is a parallelogram.
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