document.write( "Question 147483: Draw a triangle ABC, and let AM and BN be two of its medians, which intersect at G. Extend AM to the point P that makes GM = MP. Prove that PBGC is a parallelogram. \n" ); document.write( "
Algebra.Com's Answer #108440 by orca(409)![]() ![]() ![]() You can put this solution on YOUR website! PROOF\r \n" ); document.write( "\n" ); document.write( "As GM = MP, BM = MC and < BMG = < PMC, triangles BMG and PMC are congruent. \n" ); document.write( "So < GBM = < MCP. \n" ); document.write( "Thus BG is parallel to PC.\r \n" ); document.write( "\n" ); document.write( "Similarly, we can show that GC is parallel to BP.\r \n" ); document.write( "\n" ); document.write( "So PBGC is a parallelogram. \n" ); document.write( " |