document.write( "Question 148047: The number of non-business bankruptcies has increased over the years. In 2002, the number of non-business bankruptcies was 80,000 less than twice the number in 1994. If the total of non-business bankruptcies for these two years is 2,290,000 find the number of non-business bankruptcies for each year. \n" ); document.write( "
Algebra.Com's Answer #108436 by orca(409) ![]() You can put this solution on YOUR website! SOLUTION:\r \n" ); document.write( "\n" ); document.write( "Suppose the number of non-business bankruptcies was x in 1994. \n" ); document.write( "Then the number in 2002 was 2x - 80,000\r \n" ); document.write( "\n" ); document.write( "As the total of non-business bankruptcies for these two years is 2,290,000, the equation can be set up as: \n" ); document.write( "x + 2x - 80,000 = 2,290,000\r \n" ); document.write( "\n" ); document.write( "Solving for x, we have \n" ); document.write( "x + 2x = 80,000 + 2,290,000 \n" ); document.write( "3x = 2,370,000 \n" ); document.write( "x = 790,000\r \n" ); document.write( "\n" ); document.write( "So the number of non-business bankruptcies was 790,000 in 1994, and the number of non-business bankruptcies was 2x - 80,000 = 1,500,000 in 2002. \n" ); document.write( " \n" ); document.write( " |