document.write( "Question 148042: An investor has $20,000 o invest. If part is invested at 8% and the rest at 12%, how much should be invested at each rate to yield 11% on the total amount invested? \n" ); document.write( "
Algebra.Com's Answer #108428 by checkley77(12844)\"\" \"About 
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.12X+.08(20,000-X)=.11*20,000
\n" ); document.write( ".12X+1,600-.08X=2,200
\n" ); document.write( ".04X=2,200-1,600
\n" ); document.write( ".04X=600
\n" ); document.write( "X=600/.04
\n" ); document.write( "X=15,000 INVESTED @ 12%
\n" ); document.write( "20,000-15,000=5,000 INVESTED @ 8%
\n" ); document.write( "PR00F:
\n" ); document.write( ".12*15,000+.08*5,000=2,200
\n" ); document.write( "1,800+400=2,200
\n" ); document.write( "2,200=2,200
\n" ); document.write( "
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