document.write( "Question 148042: An investor has $20,000 o invest. If part is invested at 8% and the rest at 12%, how much should be invested at each rate to yield 11% on the total amount invested? \n" ); document.write( "
Algebra.Com's Answer #108428 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! .12X+.08(20,000-X)=.11*20,000 \n" ); document.write( ".12X+1,600-.08X=2,200 \n" ); document.write( ".04X=2,200-1,600 \n" ); document.write( ".04X=600 \n" ); document.write( "X=600/.04 \n" ); document.write( "X=15,000 INVESTED @ 12% \n" ); document.write( "20,000-15,000=5,000 INVESTED @ 8% \n" ); document.write( "PR00F: \n" ); document.write( ".12*15,000+.08*5,000=2,200 \n" ); document.write( "1,800+400=2,200 \n" ); document.write( "2,200=2,200 \n" ); document.write( " |