document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=148043>Question 148043</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me solve this problem,\r<BR>\n" );
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document.write( "Ten gallons of a 30% acid solution is obtained by mixing a 20% solution with a 50% solution. How much of each must be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #108421 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=108421\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x=\"gallons of 20%\", so 10-x=\"gallons of 50%\"\r<BR>\n" );
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document.write( "(20%)(x)+(50%)(10-x)=(30%)(10) Multiplying by 10 __ 2x+50-5x=30\r<BR>\n" );
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document.write( "subtracting 50 __ -3x=-20 __ dividing by -3 __ x=20/3\r<BR>\n" );
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document.write( "substituting __ 10-(20/3)=10/3 </SPAN>\n" );
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