document.write( "Question 148002: The longer leg of a right triangle is 1cm longer than the shorter leg and the hypontenuse is 5cm, then what are the lengths of the leg? \n" ); document.write( "
Algebra.Com's Answer #108396 by Electrified_Levi(103)\"\" \"About 
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Hi, Hope I can help
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\n" ); document.write( "The longer leg of a right triangle is 1 cm. longer than the shorter leg and the hypontenuse is 5cm, then what are the lengths of the leg?
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\n" ); document.write( "The shorter leg is represented by \"x\", the longer leg is (x+1)
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\n" ); document.write( "We will use the Pythagorean theorem to solve for the two sides, the Pythagorean theorem equation is
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\n" ); document.write( "\"+a%5E2+%2B+b%5E2+=+c%5E2+\"
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\n" ); document.write( "\"a\" and \"b\" are the sides, \"c\" is the hypontenuse. We will now replace \"a\", \"b\" , and \"c\"
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\n" ); document.write( "\"+%28x%2B1%29%5E2+%2B+x%5E2+=+5%5E2+\"
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\n" ); document.write( "\"+%28x%2B1%29%5E2+%2B+x%5E2+=+25+\"
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\n" ); document.write( "We will solve it even more
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\n" ); document.write( "\"+%28x%5E2+%2B+2x+%2B1%29+%2B+x%5E2+=+25+\"
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\n" ); document.write( "\"+x%5E2+%2B+2x+%2B1+%2B+x%5E2+=+25+\"
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\n" ); document.write( "\"+2%28x%29%5E2+%2B+2x+%2B1+=+25+\"
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\n" ); document.write( "We will move the \"25\" to the left side
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\n" ); document.write( "\"+2%28x%29%5E2+%2B+2x+%2B1+-25+=+25+-+25+\"
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\n" ); document.write( "\"+2%28x%29%5E2+%2B+2x+-+24+=+0+\"
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\n" ); document.write( "We can reduce the equation, we will divide everything by \"2\"
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\n" ); document.write( "\"+%282%28x%29%5E2+%2B+2x+-+24%29%2F2+=+0%2F2+\"
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\n" ); document.write( "\"+x%5E2+%2B+x+-+12+=+0+\"
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\n" ); document.write( "We can use the quadratic equation
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\n" ); document.write( "\"+x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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\n" ); document.write( "This is the original equation using \"a\", \"b\", and \"c\"
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\n" ); document.write( "\"+a%28x%29%5E2+%2B+%28b%29x+%2B+c+=+0+\"
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\n" ); document.write( "\"+x%5E2+%2B+x+-+12+=+0+\"
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\n" ); document.write( "a = 1, b = 1, c = -12
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\n" ); document.write( "Now we can replace them in the quadratic equation,
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\n" ); document.write( "\"+x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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\n" ); document.write( "\"+x+=+%28-1+%2B-+sqrt%28+1%5E2-4%2A1%2A%28-12%29+%29%29%2F%282%2A1%29+\"
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\n" ); document.write( "\"+x+=+%28-1+%2B-+sqrt%28+1-%28-48%29+%29%29%2F2+\"
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\n" ); document.write( "\"+x+=+%28-1+%2B-+sqrt%28+1+%2B+48%29%29%2F2+\"
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\n" ); document.write( "\"+x+=+%28-1+%2B-+sqrt+%2849%29+%29%2F2+\"
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\n" ); document.write( "\"+x+=+%28-1+%2B-+7+%29%2F2+\"
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\n" ); document.write( "We will use addition(if we used subtraction, the answer would be negative)
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\n" ); document.write( "\"+x+=+%28-1+%2B+7+%29%2F2+\"
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\n" ); document.write( "\"x+=+6%2F2+\"
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\n" ); document.write( "\"x+=+3+\"
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\n" ); document.write( "x = 3 cm.( lengths or measurements can't be negative, the other answer would be (-4) )( you can check by replacing \"x\" in \"+%28x%2B1%29%5E2+%2B+x%5E2+=+25+\" with \"3\"
\n" ); document.write( "or \"-4\"
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\n" ); document.write( "The shorter side was x, or 3 cm., the longer side was (x+1), or 4 cm.
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\n" ); document.write( "You can check by replacing \"a\" and \"b\" in the Pythagorean theorem equation
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\n" ); document.write( "\"+a%5E2+%2B+b%5E2+=+c%5E2+\"
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\n" ); document.write( "\"+4%5E2+%2B+3%5E2+=+5%5E2+\"
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\n" ); document.write( "\"+16+%2B+9+=+25+\"
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\n" ); document.write( "\"+25+=+25+\"
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\n" ); document.write( "Shorter side = 3 cm.
\n" ); document.write( "Longer side = 4 cm.
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\n" ); document.write( "Hope I helped, Levi
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