document.write( "Question 147986: Solve for x : 2log_base3 x - log_base3 2 = log_base3 x \n" ); document.write( "
Algebra.Com's Answer #108376 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2log_base3 x - log_base3 2 = log_base3 x \n" ); document.write( "---------- \n" ); document.write( "Note: Keep in mind this is all base 3 \n" ); document.write( "----------- \n" ); document.write( "2logx - log2 = logx \n" ); document.write( "Subtract logx from both sides to get \n" ); document.write( "logx = log2 \n" ); document.write( "x = 2 \n" ); document.write( "============== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |