document.write( "Question 147986: Solve for x : 2log_base3 x - log_base3 2 = log_base3 x \n" ); document.write( "
Algebra.Com's Answer #108376 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
2log_base3 x - log_base3 2 = log_base3 x
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\n" ); document.write( "Note: Keep in mind this is all base 3
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\n" ); document.write( "2logx - log2 = logx
\n" ); document.write( "Subtract logx from both sides to get
\n" ); document.write( "logx = log2
\n" ); document.write( "x = 2
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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