document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=22349>Question 22349</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My son needs your help in solving this problem.\r<BR>\n" );
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document.write( "Find the solution set for the system of equations<BR>\n" );
document.write( "3X + 2Y = 3<BR>\n" );
document.write( "-5X + Y = 8\r<BR>\n" );
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document.write( "Thanks<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #10835 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=10835\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve the system of equations:<BR>\n" );
document.write( "1) 3x + 2y = 3<BR>\n" );
document.write( "2) -5x + y = 8 Multiply equation 2) by 2 then subtract equation 1) from the result and solve for x.\r<BR>\n" );
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document.write( "2) -10y + 2y = 16<BR>\n" );
document.write( "1) -(3x + 2y = 3)<BR>\n" );
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document.write( "3) -13x = 13 Divide both sides by -13<BR>\n" );
document.write( "x = -1 Now substitute this into equation 1) and solve for y.\r<BR>\n" );
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document.write( "1) 3(-1) + 2y = 3 <BR>\n" );
document.write( "-3 + 2y = 3 Add 3 to both sides.<BR>\n" );
document.write( "2y = 6 Divide both sides by 2.<BR>\n" );
document.write( "y = 3\r<BR>\n" );
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document.write( "Solution: (-1, 3) </SPAN>\n" );
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