document.write( "Question 147955: The perimter of a rectangle is 66 inches. The length exceeds the width by 27 inches. Find the length and width.\r
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Algebra.Com's Answer #108341 by jim_thompson5910(35256)\"\" \"About 
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Let x=length and y=width\r
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\n" ); document.write( "\n" ); document.write( "Remember, the perimeter formula is \"P=2x%2B2y\". Since the perimeter is 66 inches, this means that \"P=66\". So the equation is now \"66=2x%2B2y\". \r
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\n" ); document.write( "\n" ); document.write( "Also, because the \"length exceeds the width by 27 inches\", this tells us that \"x=y%2B27\"\r
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\n" ); document.write( "\n" ); document.write( "\"66=2x%2B2y\" Start with the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"66=2%28y%2B27%29%2B2y\" Plug in \"x=y%2B27\"\r
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\n" ); document.write( "\n" ); document.write( "\"66=2y%2B54%2B2y\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"66=4y%2B54\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"0=4y%2B54-66\" Subtract \"66\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-4y=54-66\" Subtract \"4y\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"-4y=-12\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-12%29%2F%28-4%29\" Divide both sides by \"-4\" to isolate \"y\".\r
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\n" ); document.write( "\n" ); document.write( "\"y=3\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So the width is 3 inches. \r
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\n" ); document.write( "\n" ); document.write( "\"x=y%2B27\" Go back to the second equation.\r
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\n" ); document.write( "\n" ); document.write( "\"x=3%2B27\" Plug in \"y=3\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=30\" Add.\r
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\n" ); document.write( "\n" ); document.write( "So the length is 30 inches\r
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\n" ); document.write( "\n" ); document.write( "So the length is 30 inches and the width is 3 inches
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