document.write( "Question 147956: The perimter of a rectangle is 156m. The length is 3m more than twice the width. Find the dimensions.\r
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document.write( "What is the length ??m
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document.write( "What is the width ??m\r
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document.write( "Thanks! \n" );
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Algebra.Com's Answer #108339 by edjones(8007)![]() ![]() You can put this solution on YOUR website! L=2w+3 \n" ); document.write( "2L+2w=P \n" ); document.write( "2(2w+3)+2w=156 \n" ); document.write( "4w+6+2w=156 \n" ); document.write( "6w=150 \n" ); document.write( "w=25 m \n" ); document.write( "L=2(25)+3 \n" ); document.write( "=53 m \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( " |